初二分式计算题及答案
首页 > 初二分式计算题及答案
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求解初二数学分式题目
因为A/(x+1)+B/(x-1)=[A(x-1)+B(x+1)]/(x+1)(x-1)=[(A+B)x-(A-B)]/(x+1)(x-1), 由(x-3)/(x+1)(x-1)=A/(x+1)+B/(x-1),得: (x-3)/(x+1)(x-1)=[(A+B)x-(A-B)]/(x+1)(x-1), 所以x-3=(A+B)x-(A-B), 所以A+B=1,A-B=3, 解方程组得: A=2,B=-1...
首页 > 初二分式计算题及答案
因为A/(x+1)+B/(x-1)=[A(x-1)+B(x+1)]/(x+1)(x-1)=[(A+B)x-(A-B)]/(x+1)(x-1), 由(x-3)/(x+1)(x-1)=A/(x+1)+B/(x-1),得: (x-3)/(x+1)(x-1)=[(A+B)x-(A-B)]/(x+1)(x-1), 所以x-3=(A+B)x-(A-B), 所以A+B=1,A-B=3, 解方程组得: A=2,B=-1...